The probability of life

Estimates from the Kepler satellite suggest that there could be at least 40 billion exoplanets capable of supporting life in our galaxy alone. Given that there are perhaps 2 trillion observable galaxies, that amounts to a lot of places where life could exist. And this is only counting biochemical life as we know it. There could also be non-biochemical lifeforms that we can’t even imagine. I chatted with mathematician Morris Hirsch a long ago in Berkeley and he whimsically suggested that there could be creatures living in astrophysical plasmas, which are highly nonlinear. So let’s be generous and say that there are 10^{12} planets for biochemical life to exist in the milky way and 10^{24} total in the observable universe.

Now, does this mean that extraterrestrial life is very likely? If you listen to most astronomers and astrobiologists these days, it would seem that life is guaranteed to be out there and we just need to build a big enough telescope to find it. There are several missions in the works to detect signatures of life like methane or oxygen in the atmosphere of an exoplanet. However, the likelihood of life outside of the earth is predicated on the probability of forming life anywhere and we have no idea what that number is. Although it only took about a billion years for life to form on earth that does not really gives us any information for how likely it will form elsewhere.

Here is a simple example to illustrate how life could grow exponentially fast after it forms but take an arbitrarily long time to form. Suppose the biomass of life on a planet, x, obeys the simple equation

\frac{dx}{dt} = -x(a-x) + \eta(t)

where \eta is a zero mean stochastic forcing with variance D. The deterministic equation has two fixed points, a stable one at x = 0 and an unstable one at x = a. Thus as long as x is smaller than a life will never form but as soon as x exceeds a it will grow (super-exponentially), which will then be damped by nonlinear processes that I don’t consider. We can rewrite this problem as

\frac{dx}{dt} = -\partial_x U(x) + \eta(t)

where U = a x^2/2 - x^3/3.

Untitled.001

The probability of life is then given by the probability of escape from the well U(x) given noisy forcing (thermal bath) provided by \eta. By Kramer’s escape rate (which you can look up or I’ll derive in a future post), the rate of escape is given approximately by e^{-E/D}, where E is the well depth, which is given by a^3/6. Thus the probability of life is exponentially damped by a factor of a^3/6D. Given that we know nothing about a or D the probability of life could be anything. For example, if we arbitrarily assign a = 10^{10} and D = 10^{-10}, we get a rate (or probability if we normalize correctly) for life to be on the order of e^{-10^{40}/6}, which is very small indeed and makes life very unlikely in the universe.

Now, how could it be that there is any life in the universe at all if it had such a low probability to form at all. Well, there is no reason that there could have been lots of universes, which is what string theory and cosmology now predict. Maybe it took 10^{100} universes to exist before life formed. I’m not saying that there is no one out there, I’m only saying that an N of one does not give us much information about how likely that is.

 

Addendum, 2019-04-07: As was pointed out in the comments the model as is allows for negative biomass.  This can be corrected by adding an infinite barrier at zero (i.e. restricting x to always be positive) and this won’t affect the result.  Depending on the barrier height and noise amplitude it can take an arbitrarily long time to escape.

7 thoughts on “The probability of life

  1. Looks like a Malthusian-Langevin equation (or a stochastic Newton’s law–a 3rd order polynomial potential is where things start to get ineresting). If the USA were to annex these ET civilizations, and tax them, maybe there would be no budget deficits. https://en.wikipedia.org/wiki/Free_will_theorem of Conway and the ‘game of life’ (CA). ‘if experimenters are free to choose (milton friedman), then elementary particles can2’.

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  2. Sorry, I think I fat-fingered my comment. But I think you read what I meant rather than what I wrote :-) I meant that if x is biomass then a model for x should maintain its positive-definiteness, and that negative fluctuations near x=0 in your simple model will drive x negative. You correctly point out that we can make the model a bit more complicated to fix this. Is there a nice, closed-form solution for an absorbing or reflecting boundary at x=0 or must one simulate?

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  3. @AHD Actually, with an infinite barrier at 0 the solution should be the same. You solve it by writing down the associated Fokker-Planck equation and solving for the flux by expanding around the barrier. The boundary condition should not matter in this case as long as the barrier is far enough away from the origin.

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  4. Not sure what you mean by “as long as the barrier is far enough away from the origin”… Surely x=0 is the only physically meaningful place for the barrier. But I’m happy with the point you’re making, and I’m sure we can modify things so as to make the toy model physical and tractable. For example, u = (ax^2/2 – x^3/3 + 1) / (1-exp(-f(a)*x)) where a*f(a)>>1 will probably work fine.

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